PHP - How to pass an argument to a function by reference in PHP?

<?php
function SomeFunction(& $SomeArgument)
{
	$SomeArgument=$SomeArgument+5;
}

$TestVar=10;
SomeFunction($TestVar);

echo $TestVar; // will print 15 !!

?>

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PHP example - How to pass an argument to a function by reference in PHP?

PHP - How to pass an argument to a function by reference in PHP?